①(1/2)x2+(1/2)x+1/8=0②(x+1)(x-1)=2√2x③√3x=√2(x+1)(x-1)④2y²－7y＋2＝0
问题描述：
①(1/2)x2+(1/2)x+1/8=0②(x+1)(x-1)=2√2x③√3x=√2(x+1)(x-1)④2y²－7y＋2＝0
答
①(1/2)x2+(1/2)x+1/8=04x²+4x+1=0(2x+1)²=02x+1=0x=-1/2②(x+1)(x-1)=2√2xx²-2√2x-1=0x=(2√2±2√3)/2x=√2±√3③√3x=√2(x+1)(x-1)√3x=√2x²-√2√2x²-√3x-√2=0x=(√3±√11)/2...