(6/7+10/11+1又1/5)/(3/5+3/7+5/11)可以简算吗?
问题描述:
(6/7+10/11+1又1/5)/(3/5+3/7+5/11)可以简算吗?
答
分子
(6/7+10/11+1又1/5)
= (2* 3/7 + 2* 5/11 + 2* 3/5)
= 2 * (3/7 + 5/11 + 3/5)
= 2 分母
(6/7+10/11+1又1/5)/(3/5+3/7+5/11)=2什么意思?分子= 2 * 分母原式 = 分子/分母= 2 * 分母 /分母= 2不太懂,你能不能写得详细点。可以的分子由3个项相加6/7+10/11+1又1/56/7 = (3*2)/7 = 2 *(3/7)10/11 = (5*2)/11 = 2 *(5/11)1又1/5 = 1+ 1/5 = 5/5 + 1/5 = 6/5 =(3*2)/5 = 2 *(3/5)所以6/7+10/11+1又1/5 =(2* 3/7 + 2* 5/11 + 2* 3/5)提取共因子2= 2 * (3/7 + 5/11 + 3/5)而、分母 =3/5+3/7+5/11因为3/5+3/7+5/11 =(3/7 + 5/11 + 3/5)所以分子 = 2*分母所以 原式 = 分子/分母= 2 * 分母 /分母= 2