6x(x的平方-x+1)-(2x+3)(3x-1)
问题描述:
6x(x的平方-x+1)-(2x+3)(3x-1)
答
6*(x^2-x+1)-(2x+3)(3x-1)
=6x^2-6x+6-(6x^2+7x-3)
=6x^2-6x+6-6x^2-7x+3
=-6x+6-7x+3
=-13x+9