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(4/X+2)+(16X^3/X^4-16)+(8X/X^2+4)+(4/X-2)

分类: 作业答案 • 2022-01-09 18:03:21
问题描述：

(4/X+2)+(16X^3/X^4-16)+(8X/X^2+4)+(4/X-2)

答

4/X+2)+(16X^3/X^2-16)+(8X/X^2+4)+(4/X-2) =[4(x-2)+4(x+2)/(x+2)(x-2)+8x/(x^2+4)+16x^3/(x^4-16) =8x/(x^2-4)+8x/(x^2+4)+16x^3/(x^4-16) =8x(x^2+4+x^2-4)/(x^2+4)(x^2-4)+16x^3/(x^4-16) =16x^3/(x^4-16)+16x^3/(x^4-16) =32x^3/(x^4-16)

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