(x+2y-2分之1)(x-2y-2分之1)

问题描述:

(x+2y-2分之1)(x-2y-2分之1)

﹙x+2y-1/2﹚﹙x-2y-1/2﹚
=[﹙x-1/2﹚+2y][﹙x-1/2﹚-2y]
=﹙x-1/2﹚²-4y²
=x²-x+1/4-4y².