abc-[2ab-(3ab-bc)+4abc]
问题描述:
abc-[2ab-(3ab-bc)+4abc]
a=2.b=-2分之1.c=-1
答
abc-[2ab-(3ab-bc)+4abc]
=abc-2ab+3ab-bc-4abc
=ab-bc-4abc
=2x(-1/2)-(-1/2)x(-1)-4x2x(-1/2)x(-1)
=-1-1/2-4
=-5.5