用因式分解法解方程1.x^2=2x2.(x+1)^2-(2x-3)^2=03.x^2-6x+8=04.(1+√2)x^2-(1-√2)x=0
问题描述：
用因式分解法解方程1.x^2=2x
2.(x+1)^2-(2x-3)^2=0
3.x^2-6x+8=0
4.(1+√2)x^2-(1-√2)x=0
答
2.(x+1)^2-(2x-3)^2=（x+1+2x-3)(x+1-2x+3)=(3x-2)(4-x)=0 得：x1=2/3,x2=4
3.x^2-6x+8=(x-2)(x-4)=0 得：x1=2,x2=4
4.(1+√2)x^2-(1-√2)x=? buhuile!
答
1.x^2=2xx²-2x=0x(x-2)=0x=0或x=22.(x+1)^2-(2x-3)^2=0(x+1+2x-3)(x+1-2x+3)=0(3x-2)(4-x)=0x=3/2或x=43.x^2-6x+8=0（x-2)(x-4)=0x=2或x=44.(1+√2)x^2-(1-√2)x=0x[(1+√2)x-(1-√2)]=0x=0或x=（1-√2）/（1+...