计算:(x+5)²-2(x+5)(x+3)+(x+3)²

问题描述:

计算:(x+5)²-2(x+5)(x+3)+(x+3)²

把 x+5看成a, x+3看成b
(x+5)²-2(x+5)(x+3)+(x+3)²
=[(x+5)-(x+3)]²
=(5-3)平方
=4

原式=[x+5-(x+3)]²=2²=4

(x+5)²-2(x+5)(x+3)+(x+3)²
=(x+5-x-3)²
=2²
=4
如果本题有什么不明白可以追问,
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(x+5)²-2(x+5)(x+3)+(x+3)²
=[(x+5)-(x+3)]²
=2²
=4