5除以3(2x-5分之3)=(2x-5)除以5-9分之8

问题描述:

5除以3(2x-5分之3)=(2x-5)除以5-9分之8

等号两边同乘以45得:
75(2x-3/5)=15(2x-5)-40
150x-45=30x-75-40
120x=-70
x=-7/125(2x-3/5)/3=(2x-5)/5-8/9(10x-3)/3=(2x-5)/5-8/945*(10x-3)/3=45*(2x-5)/5-45*8/915(10x-3)=9(2x-5)-40150x-45=18x-45-40150x-45=18x-85150x-18x=85-45132x=4033x=10x=10/33这解对不对