Determine the minimum value of the sum (a/2b) + (b/4c)+ (c/8a) given that a,b,c>0.

问题描述:

Determine the minimum value of the sum (a/2b) + (b/4c)+ (c/8a) given that a,b,c>0.
如果a,b,c大于0,那么 (a/2b) + (b/4c)+ (c/8a)和的最小值是多少?
希望在一天内有正确回答.

由均值不等式易得最小值为3/4.此时b=c=2a