计算: (1)(−3/2x2y)2(2x2−4xy+7y2) (2)(-4x-3y2)(3y2-4x)

问题描述:

计算:
(1)(−

3
2
x2y)2(2x2−4xy+7y2)
(2)(-4x-3y2)(3y2-4x)

(1)原式=

9
4
x4y2(2x2-4xy+7y2),
=
9
2
x6y2−9x5y3+
63
4
x4y4

(2)原式=(-4x-3y2)(-4x+3y2),
=(-4x)2-(3y22
=16x2-9y4