(-1)^2-【1又3/7+(-12)÷6】^2×(-7/4)^3这题咋算?

问题描述:

(-1)^2-【1又3/7+(-12)÷6】^2×(-7/4)^3这题咋算?

=1-(10/7-2)²×(-7/4)³
=1-(-4/7)²×(-7/4)²×(-7/4)
=1-[(-4/7)×(-7/4)]²×(-7/4)
=1-1×(-7/4)
=1+7/4
=2又3/4