已知tanA=3,计算:(4sinA-2cosA)/(5cosA+3sinA)?(sinA-cosA)^2?

分类: 作业答案 • 2021-12-18 22:36:22

问题描述：

答

(4sinA-2cosA)/(5cosA+3sinA) =(4tanA-2)/(5+3tanA) =(4*3-2)/(5+3*3) =5/7 (sinA-cosA)^2 =1-2sinAcosA =1-sin2A =1-(2tanA/(1+tanA)) =1-2*3/(1+9) =2/5