x-1/2+1=x-1 3-2(2y-1)=3(2y-1)-2 2/7(x-7)=2-2/3x 5x+1/6=9x+1/8-1-x/3 3/2|x+5|=5 解方程

问题描述:

x-1/2+1=x-1 3-2(2y-1)=3(2y-1)-2 2/7(x-7)=2-2/3x 5x+1/6=9x+1/8-1-x/3 3/2|x+5|=5 解方程

x-1/2+1=x-1 x-1+2=2x-2 x=33-2(2y-1)=3(2y-1)-2 5=5(2y-1) 2y-1=1 y=12/7(x-7)=2-2/3x 2/7x-2=2-2/3x 1/7x+1/3x=210x=42 x=4.25x+1/6=9x+1/8-1-x/3 5x+1/6+x/3=9x+1/8-1[7x+7]/6=[9x+9-8]/8 7[x+1]/6=9[x+1]/8-128[...