(x-2y+z)(x+y-2z)分之（y-x)(z-x) + (x+y-2z)(y+z-2x)分之(z-y)(x-y) + (y+z-2z)(x-2y+z)分之（x-z)(y-z)=?

分类: 作业答案 • 2022-01-09 18:02:03

问题描述：

(x-2y+z)(x+y-2z)分之（y-x)(z-x) + (x+y-2z)(y+z-2x)分之(z-y)(x-y) + (y+z-2z)(x-2y+z)分之（x-z)(y-z)=?
第三部分那个是（y+z-2x)(x-2y+z)分之（x-z)(y-z)

答

(y+z-2z)这步有错吧

计算:(y-x)(z-x)/(x-2y+z)(x+y-2z)+(z-y)(x-y)/(x+y-2z)(y+z-2x)+(x-z)(y-z)/(y+z-2x)(x-2y+z)
化简(y-x)(z-x)/(x-2y+z)(x+y-2z)+（z-y)(x-y)/(xy-2z)(y+z-2x)+(x-z)(y-z)/(y+z-2x)(x-2y+z)速速回答
(x-2y+z)(x+y-2z)分之（y-x)(z-x) + (x+y-2z)(y+z-2x)分之(z-y)(x-y) + (y+z-2z)(x-2y+z)分之（x-z)(y-z)=?第三部分那个是（y+z-2x)(x-2y+z)分之（x-z)(y-z)
化简(y-x)(z-x)/(x-2y+z)(x+y-2z)+（z-y)(x-y)/(x-2z+y)(y+z-2x)+(x-z)(y-z)/(y+z-2x)(x-2y+z)
(x-2y+z)(x+y-2z)分之（y-x)(z-x) + (x+y-2z)(y+z-2x)分之(z-y)(x-y) + (y+z-2z)(x-2y+z)分之（x-z)(y-z)=?
化简(y-x)(z-x)/(x-2y+z)(x+y-2z)+（z-y)(x-y)/(xy-2z)(y+z-2x)+(x-z)(y-z)/(y+z-2x)(x-2y+z)
化简(y-x)(z-x)/(x-2y+z)(x+y-2z)+（z-y)(x-y)/(x-2z+y)(y+z-2x)+(x-z)(y-z)/(y+z-2x)(x-2y+z)
计算:(y-x)(z-x)/(x-2y+z)(x+y-2z)+(z-y)(x-y)/(x+y-2z)(y+z-2x)+(x-z)(y-z)/(y+z-2x)(x-2y+z)
关于因式分解的几道数学题(1) 化简a3(b－c)＋b3(c－a)＋c3(a－b)=(2) 化简a3＋b3＋c3＋bc(b＋c)＋ca(c＋a)＋ab(a＋b)=(3) 已知(a＋b)(b＋c)(c＋d)(d＋a)=(a＋b＋c＋d)(bcd＋cda＋dab＋abc),求证:ac=bd.(4) 计算(y－x)(z－x)／(x＋z－2y)(x＋y－2z) ＋ (z－y)／(x＋y－2z) × (x－y)／(y＋z－2x) ＋ (x－z)(y－z)／(y＋z－2x)(x＋z－2y).(5) 已知a＋b＋c=0,a2＋b2＋c2=1,求:a4＋b4＋c4的值.
分数乘分数的计算法则是_．
315/(36%+9%)简便方法