f(x)=sinx-cosx的最小正周期=?
问题描述:
f(x)=sinx-cosx的最小正周期=?
答
f(x)=sinx-cosx
=√2(√2/2*sinx-√2/2*cosx)
=√2(sinxcosπ/4-cosxsinπ/4)
=√2*sin(x-π/4)
f(x)=sinx-cosx的最小正周期为:T=2π/1=2π;