解方程组,√(x+1/y)+√(x-y-2)=4 2x-y+1/y=10
问题描述：
解方程组,√(x+1/y)+√(x-y-2)=4 2x-y+1/y=10
求高手解答,过程要详细
答
2x-y+1/y=10x+1/y+x-y-2=8设x+1/y=ax-y-2=ba+b=4a^2+b^2=8b=4-aa^2+(4-a)^2=8a^2+a^2-8a+16=82a^2-8a+8=0(a-2)^2=0a=2b=4-2=a√(x+1/y)=2√(x-y-2)=2x+1/y=4x-y-2=4y=x-6x+1/(x-6)=4x(x-6)+1=4(x-6)x^2-6x+1-4x+24=0...