请问,高温下,0.03mol铁和足量水蒸气反应转移的电子数为多少,

问题描述:

请问,高温下,0.03mol铁和足量水蒸气反应转移的电子数为多少,

3Fe+4H2O(g)=Fe3O4+4H2,
Fe+4/3H2O(g)=1/3Fe3O4+4/3H2,
8/3e↓→→→→→→→→→↑
也就是说1mol铁转移8/3mol电子,0.03mol铁转移0.08mol电子