3个并联电阻,通过怎样的计算过程算得R1R2R3/R1R2+R2R3+R1R3
问题描述:
3个并联电阻,通过怎样的计算过程算得R1R2R3/R1R2+R2R3+R1R3
1/R1+1/R2+1/R3是怎么划成R1R2R3/R1R2+R2R3+R1R3的?请写出计算过程
答
1/R
=1/R1+1/R2+1/R3
=(R2R3)/(R1R2R3) + (R1R3)/(R1R2R3) + (R1R2)/(R1R2R3)
=(R1R2+R2R3+R1R3) / (R1R2R3)
两边同时求倒数:
那么R不就是(R1R2R3)/(R1R2+R2R3+R1R3)