(3a+b)(___)=b²-9a²
问题描述:
(3a+b)(___)=b²-9a²
长方形周长为20 两条邻长x y,满足2(x-y)-x²+2xy-y²-1=0
答
(3a+b)(_b-3a__)=b²-9a²
长方形周长为20 两条邻长x y,满足2(x-y)-x²+2xy-y²-1=0
2(x-y)-x²+2xy-y²-1=0,则2(x-y)-(x-y)²-1=0
即-((x-y)-1)²=0
设x为长.y为宽
x+y=10,x-y=1
x=5.5,y=4.5