3^2+(4-x)^2=x^2请高人帮忙计算,尤其平方根的算法.

问题描述:

3^2+(4-x)^2=x^2请高人帮忙计算,尤其平方根的算法.

3 ² + (4 - x)² = x ²
9 + (4 - x)² = x ²
9 = x ² - (4 - x)²
9 = 【x + (4 - x)】【x - (4 - x)】(平方差公式)
9 = (x + 4 - x)(x - 4 + x)
9 = 4 (2 x - 4)
9 = 8 x - 16
8 x = 9 + 16
8 x = 25
x = 25 / 8


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