解方程2+96除以x的平方减去16=2X-1/x-4-3x-1/4-x

解方程：
2+96/(x^2-16)=(2X-1)/(x-4)-(3x-1)/(4-x)
2+96/(x^2-16)=(2X-1)/(x-4)+(3x-1)/(x-4)
2+96/(x^2-16)=(5x-2)/(x-4)
(5x-2)/(x-4)-96/(x^2-16)=2
(5x-2)((x+4)-96=2(x^2-16)
5x^2+18x-8-96=2x^2-32
3x^2+18x-72=0
x^2+6x-24=0
(x+3)^2=33
x+3=±√33
x1=-3+√33 x2=-3-√33 .