函数y=2sin(2x-π/3),x∈[π/3,3π/4]的值域
问题描述：
函数y=2sin(2x-π/3),x∈[π/3,3π/4]的值域
答
x∈[π/3,3π/4]
2x-π/3∈[π/3,7π/6]
sin在（π/3,π/2）递增
（π/2,7π/6）递减
所以最大=2snπ/2=2
最小sin7π/6=-1
值域[-1,2]