求代数式x³+x²y+xy²+y³分之x的四次方-y的四次方的值,期中x=2002,y=2001
问题描述：
求代数式x³+x²y+xy²+y³分之x的四次方-y的四次方的值,期中x=2002,y=2001
答
2007/2008x1004+2007/2008x1005—2007/2008
=2007/2008x(1004+1005-1)
=2007/2008x2008
=2007
1035413
23663103
答
原式=(x²+y²)(x²-y²)/[x(x²+y²)+y(x²+y²)]
=(x²+y²)(x+y)(x-y)/[(x+y)(x²+y²)]
=x-y
=1