设2/3扫码下载作业帮拍照答疑一拍即得
问题描述:
设2/3 扫码下载作业帮
拍照答疑一拍即得
答
f'(x)=3x^2-3ax=3x(x-a) 令f'(x)=0得x1=0,x2=a>0 [-1,0) f'(x)>0 (0,a) f'(x)
设2/3 扫码下载作业帮
拍照答疑一拍即得
f'(x)=3x^2-3ax=3x(x-a) 令f'(x)=0得x1=0,x2=a>0 [-1,0) f'(x)>0 (0,a) f'(x)