tanα=m,π

问题描述：

tanα=m,π

其他人气：949 ℃时间：2020-02-04 01:26:47

优质解答

tanα=sinα/cosα=m
cosα=sinα/m
(sinα)^2+(cosα)^2=1
(sinα)^2+(sinα/m)^2=1
(m^2+1)/m^2*(sinα)^2=1
(sinα)^2=m^2/(m^2+1)
πsinαsinα=-m/(m^2+1)^(1/2)

我来回答

类似推荐

答

tanα=sinα/cosα=m
cosα=sinα/m
(sinα)^2+(cosα)^2=1
(sinα)^2+(sinα/m)^2=1
(m^2+1)/m^2*(sinα)^2=1
(sinα)^2=m^2/(m^2+1)
πsinαsinα=-m/(m^2+1)^(1/2)