(1+1/2002+1/2004+1/2006)×(1/2002+1/2004+1/2006+1/2008)-(1+1/2002+1/2004+1/2006+1/2008)×(1/2002+1/2004+1/2006)=_.

问题描述:

(1+

1
2002
+
1
2004
+
1
2006
)×(
1
2002
+
1
2004
+
1
2006
+
1
2008
)-(1+
1
2002
+
1
2004
+
1
2006
+
1
2008
)×(
1
2002
+
1
2004
+
1
2006
)=______.

设12002+12004+12006=a,12002+12004+  12006+12008=b,原式变为(1+a)×b-(1+b)×a,=b+ab-a-ab,=b-a,=12002+12004+12006+ 12008-(12002+12004+12006),=12008.故答案为:12008....