(1+1/2002+1/2004+1/2006)×(1/2002+1/2004+1/2006+1/2008)-(1+1/2002+1/2004+1/2006+1/2008)×(1/2002+1/2004+1/2006)=_.
问题描述:
(1+
+1 2002
+1 2004
)×(1 2006
+1 2002
+1 2004
+1 2006
)-(1+1 2008
+1 2002
+1 2004
+1 2006
)×(1 2008
+1 2002
+1 2004
)=______. 1 2006
答
设12002+12004+12006=a,12002+12004+ 12006+12008=b,原式变为(1+a)×b-(1+b)×a,=b+ab-a-ab,=b-a,=12002+12004+12006+ 12008-(12002+12004+12006),=12008.故答案为:12008....