∫(x^2-2x+4)^(-3/2)dx
问题描述：
∫(x^2-2x+4)^(-3/2)dx
答
设(x-1)/√3=tant
=3^(-3/2)∫sec^(-3)t*√3sec^2(t)dt
=(1/3)∫costdt=(1/3)sint+C
=(1/3)(x-1)/(x^2-2x+4)^(1/2)+C