化简分式[x/(x+1)-2/(x^2-1)]÷(x^2-4)/(x^2-2x+1)
问题描述:
化简分式[x/(x+1)-2/(x^2-1)]÷(x^2-4)/(x^2-2x+1)
答
解原式=[x(x-1)/(x-1)(x+1)-2/(x+1)(x-1)]÷(x-2)(x+2)/(x-1)²=[(x²-x-2)/(x-1)(x+1)]×(x-1)²/(x-2)(x+2)=(x-2)(x+1)/(x-1)(x+1)×(x-1)²/(x-2)(x+2)=(x-2)/(x-1)×(x-1)²/(x-2)(x+2)=(x-...