(1)X-3/X-1+X²-2/(x-1)(X-7)=1+x-5/x-7 (2)2x-1/x+4-5=96/x²-16-1-3x/4-x

问题描述:

(1)X-3/X-1+X²-2/(x-1)(X-7)=1+x-5/x-7 (2)2x-1/x+4-5=96/x²-16-1-3x/4-x

(1)(X-3)/(X-1)+(X²-2)/(x-1)(X-7)=1+(x-5)/(x-7)
两边同乘以(x-1)(X-7)得:
(x-3)(x-7)+X²-2=(x-1)(x-7)+(x-5)(x-1)
4x=-7
x=-7/4
代入原方程验证:x=-7/4是原方程的解.
(2)(2x-1)/(x+4)-5=96/(x²-16)-(1-3x)/(4-x)
两边同乘以(x²-16)得:
(2x-1)(x-4)+5(X²-16)=96+(1-3x)(x+5)
2x²-5x-37=0
x=(5±√321)/4
代入原方程验证:x=(5±√321)/4都是原方程的解.第二题好像不对耶!我也觉得有问题,是不是原题的数字有误。