用因式分解法解下列方程 1. x(x-1/2)=x 2. 1/2(x-2)^2+x-2=0 3. 9(2x+3)^2-4(2x-5)^2=0
问题描述:
用因式分解法解下列方程 1. x(x-1/2)=x 2. 1/2(x-2)^2+x-2=0 3. 9(2x+3)^2-4(2x-5)^2=0
答
1.x(x-1/2)=x x(x-1/2)-x=0x(x-1/2-1)=0x(x-3/2)=0x=0或x=3/22.1/2(x-2)^2+x-2=0 1/2(x-2)(x-2+2)=01/2x(x-2)=0x=0或x=23.9(2x+3)^2-4(2x-5)^2=0[3(2x+3)+2(2x-5)][3(2x+3)-2(2x-5)]=0(10x-1)(2x+19)=0x=1/10或x=-19...