数学题:(180°-91°32'24'')÷3 34°25'×3+35°42'

问题描述:

数学题:(180°-91°32'24'')÷3 34°25'×3+35°42'

  •  (180°-91°32'24'')÷3 

  • =(179°59'60''-91°32′24″)÷3 

  • =88°27′36″÷3 

  • =88/3°9′12″

34°25'×3+35°42'

=102°75′+35°42'

=137°117′

=138°57′

数学题:(180°-91°32'24'')÷3 =(179°59'60''-91°32'24'')÷3=88°27'36''÷3=87°87'36''÷3==29°29'12''

34°25'×3+35°42'=102°75'+35°42'=103°15'+35°42'=(103°+35°)+(15'+42')=138°57'.

29。29'12''
138。57'

你这是两个式子吗?@_@
(1)原式=88°27'36"÷3=29°29'12"
(2)原式=103°15'+35°42'=138°57'

(180°-91°32'24'')÷3
=88°27'36''÷3
=87°87'36''÷3
=29°29'12''
34°25'×3+35°42'
=102°75'+35°42'
=137°117'
=138°57'

1.解:原式=(179°59′60″-91°32'24'')÷3 =88°27′36″÷3=29°29′12″
2.解:原式=102°75′+35°42′=137°117′=138°57′


注明除法
88°27′36″)÷3=29°......1°27′36″
1°27′36″=87′36″
87′36″÷3=29′12″

60分为一度,估计你是不懂这个换算。