6x+4(10-x)=41+1
问题描述:
6x+4(10-x)=41+1
答
6x+4(10-x)=41+1
6x+40-4x=42
2x=2
x=1
答
6x+40-4x=42
2x=2
x=1
答
6x+4(10-x)=41+1
6x+40-4x=41+1
2x=2
x=1