6x+4(10-x)=41+1

问题描述:

6x+4(10-x)=41+1

6x+4(10-x)=41+1
6x+40-4x=42
2x=2
x=1

6x+40-4x=42
2x=2
x=1

6x+4(10-x)=41+1
6x+40-4x=41+1
2x=2
x=1