已知方程3x+4y+6=0,求4(2y+3x)-3(2x-4)的值,

问题描述:

已知方程3x+4y+6=0,求4(2y+3x)-3(2x-4)的值,

4(2y+3x)-3(2x-4)
=8y+12x-6x+12
=6x+8y+12
=2(3x+4y+6)
=2×0
=0

原式=8y+12x-6x+12
=6x+8y+12
=2(3x+4y+6)
=2×0
=0

4(2y+3x)-3(2x-4)
=8y+12x-6x+12
=6x+8y+12
=2(3x+4y+6)
=0