解方程组:3(x-3)+10(2/3+y)=13,22(x-3)+5(2/3+y)=27
问题描述：
解方程组:3(x-3)+10(2/3+y)=13,22(x-3)+5(2/3+y)=27
答
3(x-3)+10(2/3+y)=13 (1)
22(x-3)+5(2/3+y)=27 (2)
(2)*2-(1)得
44(x-3)+10(2/3+y)-3(x-3)-10(2/3+y)=54-13
41(x-3)=41
x-3=1
x=4
将x=4代入(1)得
3(4-3)+10(2/3+y)=13
3+10(2/3+y)=13
10(2/3+y)=10
2/3+y=1
y=1/3