用十字相乘法来分解因式：(1)x^2y^2-5/6xy-1/6=?(2)8x^2-6x-35=?
问题描述：
用十字相乘法来分解因式：(1)x^2y^2-5/6xy-1/6=?(2)8x^2-6x-35=?
答
x^2y^2-5/6xy-1/6
= (xy+1/6)(xy-1)
8x^2-6x-35
= (4x+7)(2x-5)
答
x^2y^2-5/6xy-1/6=1/6（6x^2y^2-5xy-1）=1/6（xy-1)(6xy+1)
8x^2-6x-35=(2x-5)(4x+7)
答
(1)x^2y^2-5/6xy-1/6=1/6(6x²y²-5xy-1)=1/6(6xy+1)(xy-1)
(2)8x^2-6x-35=(2x-5)(4x+7)