根号下1+sinx dx 求积分
问题描述：
根号下1+sinx dx 求积分
答
1+sinx=(sin(x/2)+cos(x/2))^2
即原式=∫（sin(x/2)+cos(x/2)）dx
=2∫sin(x/2)d(x/2)+2∫cos(x/2)d(x/2)
=2sin(x/2)-2cos(x/2)