当x>2时,化简代数式根号(x+2根号(x-1))-根号(x-2根号(x-1))
问题描述:
当x>2时,化简代数式根号(x+2根号(x-1))-根号(x-2根号(x-1))
答
√[x+2√﹙x-1﹚]-√[x-2√﹙x-1﹚] =√[﹙x-1﹚+2√﹙x-1﹚+1]-√[﹙x-1﹚-2√﹙x-1﹚+1] =√[√﹙x-1﹚+1]²-√[﹙x-1﹚-1]² =|√﹙x-1﹚+1|-|√﹙x-1﹚-1| ∵x>2...