计算下列公式 (1）（2lg2+lg3)/(1+1/2lg0.36+1/3lg8) (2) lg5^2+2/3lg8+lg5*lg20+(lg2)^2

1.(2lg2+lg3)/(1+0.5lg0.36+1/3lg8)
=(lg4+lg3)/(1+lg√0.36 +lg(2^3)^(1/3))
=lg12/(1+lg0.6+lg2)
=lg12/(lg10+lg0.6+lg2)
=lg12/lg(10*0.6*2)
=lg12/lg12
=1

原式=lg12/(lg10+lg0.6+lg3)=lg12/lg18=log18(12)原式=2lg5+2lg2+lg5*(2lg2+lg5)+(lg2)²=(lg5)²+2lg5lg2+(lg2)²+2(lg5+lg2)=(lg5+lg2)²+2lg10=(lg10)²+2=1+2=3