7 7 3 3 这四个数字加减乘除无论怎么算要能等于24,要怎么算啊?

问题描述:

7 7 3 3 这四个数字加减乘除无论怎么算要能等于24,要怎么算啊?

1: (3 + 3 ÷ 7) × 7
2: (3 + (3 ÷ 7)) × 7
3: (3 ÷ 7 + 3) × 7
4: ((3 ÷ 7) + 3) × 7
5: 7 × (3 + 3 ÷ 7)
6: 7 × (3 + (3 ÷ 7))
7: 7 × (3 ÷ 7 + 3)
8: 7 × ((3 ÷ 7) + 3)
给分。。

7*((3/7)+3)
7*(3+(3/7))
7*((3/7)+3)
7*(3+(3/7))
7*((3/7)+3)
7*(3+(3/7))
7*((3/7)+3)
7*(3+(3/7))
((3/7)+3)*7
((3/7)+3)*7
(3+(3/7))*7
(3+(3/7))*7
((3/7)+3)*7
((3/7)+3)*7
(3+(3/7))*7
(3+(3/7))*7