计算log3[(9^2 * 27^(1/3))/3^(log3 234)]
问题描述：
计算log3[(9^2 * 27^(1/3))/3^(log3 234)]
答
log3[(9^2 * 27^(1/3))/3^(log3 234)]
=log3[3^4*3^(3*1/3))/3^(log3 (3^2*26)]
=log3[3^5/3^(2+log3 26)]
=log3[3^(5-(2+log3 26)]
=log3 [3^(3-log3 26)]
=3-log3 26
答
[(9^2 * 27^(1/3))/3^(log3 234)]=(9^2 * 27^(1/3))/3^(log3 234)=(81*3)/(234)=3^5/234log3[(9^2 * 27^(1/3))/3^(log3 234)]=log3(3^5/234)=5-log3(234)另外这里是不是243啊 如果是243的话,那就等于=5-log3(243)=5-...