填括号里的 使等式成立 -3x^2+4/2x^2-5x-4=- 3x^2-4/( )2-x/-x^2+3=( )/x^2-3a^2+3a+2/a^2+6a+5=( )/a+52-x/-x^2+3=( )/x^2-3 a^2+3a+2/a^2+6a+5=( )/a+5
问题描述:
填括号里的 使等式成立 -3x^2+4/2x^2-5x-4=- 3x^2-4/( )
2-x/-x^2+3=( )/x^2-3a^2+3a+2/a^2+6a+5=( )/a+5
2-x/-x^2+3=( )/x^2-3 a^2+3a+2/a^2+6a+5=( )/a+5
答
(-3x^2+4)/(2x^2-5x-4)=- (3x^2-4)/( 2x²-5x-4 )
(2-x)/(-x^2+3)=( X-2 )/(x^2-3)
(a^2+3a+2)/(a^2+6a+5)=( a+2)/(a+5)