矩形ABCD各顶点的坐标分别为:(-5,-1),(3,-1),(3,3),(-5,3),若直线Y=kx+4将矩形ABCD的面积等分,则k=
问题描述:
矩形ABCD各顶点的坐标分别为:(-5,-1),(3,-1),(3,3),(-5,3),若直线Y=kx+4将矩形ABCD的面积等分,则k=
答
根据判断,直线应于ab,cd,相较于两点e(-5/k,-1) f(-1/k,3)
矩形ABCD的面积等分,故
ae=cf
即:-5-(-5/K)=3-(-1/K)
K=1/2