解方程:x^2-6x-(x-3)的绝对值+3=0

问题描述:

解方程:x^2-6x-(x-3)的绝对值+3=0

x^2-6x-|x-3|+3=0
当 x>=3时,x^2-6x-x+3+3=0 x^2-7x+6=0 (x-6)(x-1)=0
x=1(舍去),x=6
当 xx=0, x=5(舍去)
此方程解为 x=0, x=6

x²-6x-|x-3|+3=0
当x≥3时,x²-6x-x+3+3=0,即:x²-7x+6=0 (x-1)(x-6)=0 x1=1 x2=6,舍去x1=1
当x