分解因式2y∧2+3xy+x∧2+3+4x+7y

分类: 作业答案 • 2022-01-02 13:32:13

问题描述：

答

=x²+3xy+2y²+4x+7y+3
=(x+2y)(x+y)+3x+4y+3
=(x+2y+1)(x+y+3)

答

原式=(x+2y)(x+y)+3(x+2y)+(x+y)+3
=(x+2y)(x+y+3)+(x+y+3)
=(x+y+3)(x+2y+1)

答

2y^2+3xy+x^2+3+4x+7y
=x^2+3xy+2y^2+4x+7y+3
=(x+2y)(x+y)+4x+7y+3
=(x+y+3)(x+2y+1)