初一数学解方程：（y+4)/5-(y-5)=(y+3)/3-(y-2)/2

(y+4)/5-（y-5）=（y+3）/3-（y-2)/2 两边同乘以30
最后得出y=6

（y+4)/5-(y-5)=(y+3)/3-(y-2)/2
6（y+4) - y+5=10(y+3)-15(y-2)
6y+24-y+5=10y+30-15y+30
6y-y-10y+15y=30+30-5-24
10y =31
y=3.1

先化简，得，6（y+4)-30（y-5）=10(y+3)-15(y-2)
(6-30)y+(24+150)=(10-15)y+(30+30)
-24y+174=-5y+60
19y=114
y=6

y=6

(y + 4)/5 - (y - 5) = (y + 3)/3 - (y - 2)/2两边同时乘以 30 得:6(y + 4) - 30(y - 5) = 10(y + 3) - 15(y - 2)6y + 24 - 30y + 150 = 10y + 30 - 15y + 30-24y + 174 = -5y + 6019y = 114y = 6

：（y+4)/5-(y-5)=(y+3)/3-(y-2)/2
6y+24-30y+150=10y+30-15y+30
6y-30y-10y+15y=30+30-24-150
-19y=-114
y=6

左右两边同乘以30得
6y+24-30y+150=10y+30-15y+30
化简得19y=114
解得y-6