计算（x+1/x)(x2+1/x2)(x4+1/x4)…（x16+1/x16)(x2-1)
问题描述：
计算（x+1/x)(x2+1/x2)(x4+1/x4)…（x16+1/x16)(x2-1)
数字代表几次幂,1/x2读作x的二次幂分之一,
答
原式=（x+1/x)(x-1/x)(x^2+1/x^2)……(x^16+1/x^16)(x^2-1)/(x-1/x)=(x^2-1/x^2)(x^2+1/x^2)(x^4+1/x^4)……(x^16+1/x^16)(x^2-1)/(x-1/x)=……=(x^16-1/x^16)(x^16+1/x^16)(x^2-1)/(x-1/x)=(x^32-1/x^32)(x^2-1)/(x...