2x^3+(2a+23)x²+(10-7a)x+3a-11,怎么因式分解?
问题描述：
2x^3+(2a+23)x²+(10-7a)x+3a-11,怎么因式分解?
答
=2x^3+2ax^2+23x^2+10x-7ax+3a-11
=2x^3+23x^2+10x-11+a(2x^2-7x+3)
=2x^3-x^2+24x^2+10x-11+a(2x-1)(x-3)
=x^2(2x-1)+(2x-1)(12x+11)+a(2x-1)(x-3)
=(2x-1)(x^2+12x+11+ax-3a)