解二元一次方程y/3-(x+1)/6=3 (x-3)/4-(y-3)/3=1/6
问题描述:
解二元一次方程y/3-(x+1)/6=3 (x-3)/4-(y-3)/3=1/6
答
2y-x-1=18
3x-9-4y+12=2
=>
2y-x=19(1)
-4y+3x=-1(2)
(1)*2+(2)得
x=37
y=28