(x-2)^2-25x^2=0怎样因式分解?
问题描述:
(x-2)^2-25x^2=0怎样因式分解?
答
=x^2-4x+4-25x^2=-24x^2-4x+4=-4(6x^2+x-1)=-4(3x-1)(2x+1)
(x-2)^2-25x^2=0怎样因式分解?
=x^2-4x+4-25x^2=-24x^2-4x+4=-4(6x^2+x-1)=-4(3x-1)(2x+1)